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MHT CET 2026 (19 Apr, Shift 1) · Diffraction at a Single Slit

Diffraction at a Single Slit question from MHT CET 2026 (19 Apr, Shift 1)

Q12MHT CET 2026 · 19 APR · SHIFT 1Medium

Diffraction at a Single Slit

In a single slit diffraction pattern, the distance between the plane of the slit and the screen is 1.41.4 m. The width of the slit is 0.660.66 mm. The second maximum is formed at the distance of 2.82.8 mm from the center of the screen. The wavelength of light used is

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Answer: (c)

  1. Second secondary maximum: y=5λD2a⇒λ=2ay5Dy = \dfrac{5\lambda D}{2a} \Rightarrow \lambda = \dfrac{2ay}{5D}
  2. λ=2×0.66×10−3×2.8×10−35×1.4=5.28×10−7\lambda = \dfrac{2 \times 0.66 \times 10^{-3} \times 2.8 \times 10^{-3}}{5 \times 1.4} = 5.28 \times 10^{-7} m
  3. So the answer is (c) 52805280 Å.
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