In a single slit experiment, a parallel beam of green light of wavelength 550 nm passes through a slit of width 0.20 mm. The transmitted light is collected on a screen 100 cm away. The distance of first order minima from the central maximum will be x × 10⁻⁵ m. The value of x is: Numerical answer type. Work it out, then open the answer.

Answer: 275. First minimum on the screen: y₁ = (Dλ)/(a). y₁ = 1 × 550×10⁻⁹0.20×10⁻³ = 2.75×10⁻³ m = 275×10⁻⁵ m So x = 275.

In a single slit experiment, a parallel beam of green light of… | JEE Main 2024 (5 Apr, Shift 2)

Q26JEE Main 2024 · 5 APR · SHIFT 2Easy

Diffraction at a Single Slit

In a single slit experiment, a parallel beam of green light of wavelength $550\text{ nm}$ passes through a slit of width $0.20\text{ mm}$ . The transmitted light is collected on a screen $100\text{ cm}$ away. The distance of first order minima from the central maximum will be $x \times 10^{-5}\text{ m}$ . The value of $x$ is:

Numerical answer type. Work it out, then open the answer.

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Answer: 275

First minimum on the screen: $y_1 = \dfrac{D\lambda}{a}$ .
$y_1 = \dfrac{1 \times 550\times10^{-9}}{0.20\times10^{-3}} = 2.75\times10^{-3}\text{ m} = 275\times10^{-5}\text{ m}$
So $x = 275$ .

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