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NEET 2026 (Re-neet) · Kepler's Laws & Planetary Motion

Kepler's Laws & Planetary Motion question from NEET 2026 (Re-neet)

Q1NEET 2026 · RE-NEETEasy

Kepler's Laws & Planetary Motion

In a solar system, the time-period of revolution of a planet tracing a circular orbit of radius $R$ is proportional to:

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Answer: (c)

Gravity gives the centripetal force: $\dfrac{GMm}{R^2} = m\dfrac{4\pi^2}{T^2}R \Rightarrow T^2 = \dfrac{4\pi^2}{GM}R^3$ .
$T \propto R^{3/2}$
So the answer is (c) $R^{3/2}$ .

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