In a system two particles of masses m₁ = 3 kg and m₂ = 2 kg are placed at certain distance from each other. The particle of mass m₁ is moved towards the center of mass of the system through a distance 2 cm. In order to keep the center of mass of the system at the original position, the particle of mass m₂ should move towards the center of mass by the distance _________ cm. Numerical answer type. Work it out, then open the answer.

Answer: 3. CM unchanged: m₁ d₁ = m₂ d₂ 3 × 2 = 2 × d₂ d₂ = 3 cm

In a system two particles of masses m₁ = 3 kg and m₂ = 2 kg are… | JEE Main 2024 (4 Apr, Shift 2)

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Centre of Mass of Discrete Particles

In a system two particles of masses $m_1 = 3\text{ kg}$ and $m_2 = 2\text{ kg}$ are placed at certain distance from each other. The particle of mass $m_1$ is moved towards the center of mass of the system through a distance $2\text{ cm}$ . In order to keep the center of mass of the system at the original position, the particle of mass $m_2$ should move towards the center of mass by the distance _________ $\text{cm}$ .

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 3

CM unchanged: $m_1 d_1 = m_2 d_2$
$3 \times 2 = 2 \times d_2$
$d_2 = 3$ cm

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