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JEE Main 2002 (AIEEE) · AC Generator & Transformer

AC Generator & Transformer question from JEE Main 2002 (AIEEE)

Q58JEE Main 2002 · AIEEEEasy

AC Generator & Transformer

In a transformer, number of turns in the primary coil are $140$ and that in the secondary coil are $280.$ If current in primary coil is $4A,$ then that in the secondary coil is

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Answer: (b)

Ideal transformer: $I_s = I_p\dfrac{N_p}{N_s}$ .
$I_s = 4 \times \dfrac{140}{280} = 2\text{ A}$
So the answer is (b) 2 A.

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