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MHT CET 2025 (20 Apr, Shift 1) · Junction Transistor

Junction Transistor question from MHT CET 2025 (20 Apr, Shift 1)

Q32MHT CET 2025 · 20 APR · SHIFT 1Medium

Junction Transistor

In a transistor (common emitter configuration) the ratio of power gain to voltage gain is ( $\alpha$ and $\beta$ are current ratios)

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Answer: (d)

Power gain $= \dfrac{P_o}{P_i} = \dfrac{I_C V_o}{I_B V_i} = \beta \times A_V$
So $\dfrac{\text{power gain}}{\text{voltage gain}} = \beta$ .
So the answer is (d) $\beta$ .

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