In a vector p, 'x' and 'y' components have magnitudes 2 units and 5 units respectively. A vector q, along negative Y axis has magnitude of 3 units. Then p · q is (a) -6 (b) -9 (c) -10 (d) -15

Answer: (d). p = 2i + 5j, q = -3j. p · q = (2)(0) + (5)(-3) = -15 So the answer is (d) -15.

In a vector p, 'x' and 'y' components have magnitudes 2 units and 5… | MHT CET 2026 (19 May, Shift 1)

Q2MHT CET 2026 · 19 MAY · SHIFT 1Easy

Scalar (Dot) Product

In a vector $\vec{p}$ , 'x' and 'y' components have magnitudes 2 units and 5 units respectively. A vector $\vec{q}$ , along negative Y axis has magnitude of 3 units. Then $\vec{p} \cdot \vec{q}$ is

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Answer: (d)

$\vec{p} = 2\hat{i} + 5\hat{j}$ , $\vec{q} = -3\hat{j}$ .
$\vec{p} \cdot \vec{q} = (2)(0) + (5)(-3) = -15$
So the answer is (d) $-15$ .

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Scalar (Dot) Product question from MHT CET 2026 (19 May, Shift 1)

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