In a Vernier Calipers, 10 divisions of Vernier scale are equal to the 9 divisions of main scale. When both jaws of Vernier calipers touch each other, the zero of the Vernier scale is shifted to the left of zero of the main scale and 4 th Vernier scale division exactly coincides with the main scale reading. One main scale division is equal to 1 mm. While measuring diameter of a spherical body, the body is held between two jaws. It is now observed that zero of the Vernier scale lies between 30 and 31 divisions of main scale reading and 6 th Vernier scale division exactly coincides with the main scale reading. The diameter of the spherical body will be: (a) 3.02 cm (b) 3.06 cm (c) 3.10 cm (d) 3.20 cm

Answer: (c). LC = 1 MSD - 1 VSD = 1 - 0.9 = 0.1 mm Vernier zero left of main zero: negative zero error, taken as -4× 0.1 = -0.4 mm Observed reading = 30 + 6× 0.1 = 30.6 mm Diameter = 30.6 - (-0.4) = 31.0 mm = 3.10 cm. So the answer is (c).

In a Vernier Calipers, 10 divisions of Vernier scale are equal to the… | JEE Main 2022 (26 Jul, Shift 2)

Q38JEE Main 2022 · 26 JUL · SHIFT 2Difficult

Least Count, Vernier Callipers & Screw Gauge

In a Vernier Calipers, 10 divisions of Vernier scale are equal to the 9 divisions of main scale. When both jaws of Vernier calipers touch each other, the zero of the Vernier scale is shifted to the left of zero of the main scale and $4$ th Vernier scale division exactly coincides with the main scale reading. One main scale division is equal to $1\text{ mm}$ . While measuring diameter of a spherical body, the body is held between two jaws. It is now observed that zero of the Vernier scale lies between 30 and 31 divisions of main scale reading and $6$ th Vernier scale division exactly coincides with the main scale reading. The diameter of the spherical body will be:

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Answer: (c)

LC $= 1\text{ MSD} - 1\text{ VSD} = 1 - 0.9 = 0.1\text{ mm}$
Vernier zero left of main zero: negative zero error, taken as $-4\times 0.1 = -0.4\text{ mm}$
Observed reading $= 30 + 6\times 0.1 = 30.6\text{ mm}$
Diameter $= 30.6 - (-0.4) = 31.0\text{ mm} = 3.10\text{ cm}$ . So the answer is (c).

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