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NEET 2026 · Least Count, Vernier Callipers & Screw Gauge

Least Count, Vernier Callipers & Screw Gauge question from NEET 2026

Q1NEET 2026Easy

Least Count, Vernier Callipers & Screw Gauge

In a vernier calliper, 20 VSD coincide with 16 MSD (each division of length 1 mm ). The least count of the vernier callipers is:

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Answer: (c)

$20\text{ VSD} = 16\text{ MSD} \Rightarrow 1\text{ VSD} = 0.8$ mm.
LC $= 1\text{ MSD} - 1\text{ VSD} = 1 - 0.8 = 0.2$ mm
So the answer is (c) $0.02$ cm.

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