In a vernier callipers, 50 vernier scale divisions are equal to 48 main scale divisions. If one main scale division = 0.05 mm, then the least count of the vernier callipers is ______ mm. (a) 0.002 (b) 0.02 (c) 0.05 (d) 0.005

Answer: (a). 50 VSD = 48 MSD ⇒ 1 VSD = 48/50 MSD LC = (1 - 48/50)MSD = 2/50× 0.05 mm = 0.002 mm, answer (a).

In a vernier callipers, 50 vernier scale divisions are equal to 48… | JEE Main 2026 (24 Jan, Shift 2)

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Least Count, Vernier Callipers & Screw Gauge

In a vernier callipers, 50 vernier scale divisions are equal to 48 main scale divisions. If one main scale division $= 0.05\text{ mm}$ , then the least count of the vernier callipers is ______ mm.

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Answer: (a)

$50\text{ VSD} = 48\text{ MSD} \Rightarrow 1\text{ VSD} = \dfrac{48}{50}$ MSD
LC $= \left(1 - \dfrac{48}{50}\right)\text{MSD} = \dfrac{2}{50}\times 0.05$ mm
$= 0.002$ mm, answer (a).

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