In a wheatstone's bridge, three resistances P, Q and R are connected in the three arms and the fourth arm is formed by two resistances S₁ and S₂ connected in parallel. The condition for the bridge to be balanced is (a) P/Q = (2R)/(S₁+S₂) (b) P/Q = (R(S₁+S₂))/(2S₁S₂) (c) P/Q = (R(S₁+S₂))/(S₁S₂) (d) P/Q = (R(S₁S₂))/(S₁+S₂)

Answer: (c). Fourth arm: S = (S₁ S₂)/(S₁ + S₂) Balance: P/Q = R/S = (R(S₁+S₂))/(S₁ S₂) So the answer is (c).

In a wheatstone's bridge, three resistances P, Q and R are connected… | MHT CET 2021 (22 Sep, Shift 1)

Q55MHT CET 2021 · 22 SEP · SHIFT 1Medium

Wheatstone Bridge & Metre Bridge

In a wheatstone's bridge, three resistances $\mathrm{P, Q}$ and $\mathrm{R}$ are connected in the three arms and the fourth arm is formed by two resistances $S_1$ and $S_2$ connected in parallel. The condition for the bridge to be balanced is

Show answer and solution

Answer: (c)

Fourth arm: $S = \dfrac{S_1 S_2}{S_1 + S_2}$
Balance: $\dfrac{P}{Q} = \dfrac{R}{S} = \dfrac{R(S_1+S_2)}{S_1 S_2}$
So the answer is (c).

Report a mistake

Wheatstone Bridge & Metre Bridge question from MHT CET 2021 (22 Sep, Shift 1)

More questions on Wheatstone Bridge & Metre Bridge