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JEE Main 2022 (28 Jul, Shift 1) · YDSE: Fringe Width & Fringe Positions

YDSE: Fringe Width & Fringe Positions question from JEE Main 2022 (28 Jul, Shift 1)

Q41JEE Main 2022 · 28 JUL · SHIFT 1Easy

YDSE: Fringe Width & Fringe Positions

In a Young's double slit experiment, a laser light of 560 nm produces an interference pattern with consecutive bright fringes' separation of 7.2 mm. Now another light is used to produce an interference pattern with consecutive bright fringes' separation of 8.1 mm. The wavelength of second light is __________ nm.

Numerical answer type. Work it out, then open the answer.

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Answer: 630

$\beta = \frac{\lambda D}{d}$ , so $\beta \propto \lambda$ for the same setup
$\lambda_2 = \lambda_1 \frac{\beta_2}{\beta_1} = 560 \times \frac{8.1}{7.2}$
So $\lambda_2 = 630$ nm.

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