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JEE Main 2026 (21 Jan, Shift 2) · YDSE: Film, Medium & Two Wavelengths

YDSE: Film, Medium & Two Wavelengths question from JEE Main 2026 (21 Jan, Shift 2)

Q15JEE Main 2026 · 21 JAN · SHIFT 2Medium

YDSE: Film, Medium & Two Wavelengths

In a Young's double slit experiment set up, the two slits are kept 0.4 mm apart and screen is placed at 1 m from slits. If a thin transparent sheet of thickness 20 μm20\ \mu\text{m} is introduced in front of one of the slits then center bright fringe shifts by 20 mm on the screen.

The refractive index of transparent sheet is given by α10\frac{\alpha}{10}, where α\alpha is ______.

Numerical answer type. Work it out, then open the answer.

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Answer: 14

  1. Shift y=(μ−1)tDdy = \dfrac{(\mu - 1)tD}{d}.
  2. μ−1=ydtD=(20×10−3)(0.4×10−3)(20×10−6)(1)=0.4\mu - 1 = \dfrac{y d}{tD} = \dfrac{(20\times10^{-3})(0.4\times10^{-3})}{(20\times10^{-6})(1)} = 0.4
  3. μ=1.4=1410\mu = 1.4 = \frac{14}{10}, so α=14\alpha = 14.
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