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JEE Main 2014 (19 Apr, Shift 1) · Diffraction at a Single Slit

Diffraction at a Single Slit question from JEE Main 2014 (19 Apr, Shift 1)

Q84JEE Main 2014 · 19 APR · SHIFT 1Medium

Diffraction at a Single Slit

In a Young's double slit experiment, the distance between the two identical slits is 6.1 times larger than the slit width. Then the number of intensity maxima observed within the central maximum of the single slit diffraction pattern is:

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Answer: (c)

  1. Central maximum spans sin⁡θ\sin\theta from −λa-\dfrac{\lambda}{a} to +λa+\dfrac{\lambda}{a}; interference maxima are spaced λd\dfrac{\lambda}{d} apart.
  2. Number of maxima ≈2λ/aλ/d=2da=2×6.1=12.2\approx \dfrac{2\lambda/a}{\lambda/d} = \dfrac{2d}{a} = 2 \times 6.1 = 12.2
  3. So the answer is (c) 1212.
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