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JEE Main 2019 (9 Jan, Shift 2) · YDSE: Film, Medium & Two Wavelengths

YDSE: Film, Medium & Two Wavelengths question from JEE Main 2019 (9 Jan, Shift 2)

Q62JEE Main 2019 · 9 JAN · SHIFT 2Difficult

YDSE: Film, Medium & Two Wavelengths

In a Young's double slit experiment, the slits are placed 0.320 mm apart. Light of wavelength λ\lambda = 500 nm is incident on the slits. The total number of bright fringes that are observed in the angular range −- 30°≤θ≤\le \theta \le30° is:

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Answer: (d)

  1. Bright fringe: dsin⁡θ=nλd\sin\theta = n\lambda.
  2. nmax=dsin⁡30∘λ=0.32×10−3×0.5500×10−9=320n_{max} = \frac{d\sin 30^\circ}{\lambda} = \frac{0.32\times10^{-3}\times 0.5}{500\times10^{-9}} = 320.
  3. Fringes on each side: 320, plus the central one: 2(320)+1=6412(320)+1 = 641.
  4. So the answer is (d) 641.
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