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JEE Main 2021 (24 Feb, Shift 1) · Superposition, Coherence & Intensity

Superposition, Coherence & Intensity question from JEE Main 2021 (24 Feb, Shift 1)

Q78JEE Main 2021 · 24 FEB · SHIFT 1Medium

Superposition, Coherence & Intensity

In a Young's double slit experiment, the width of the one of the slit is three times the other slit. The amplitude of the light coming from a slit is proportional to the slit-width. Find the ratio of the maximum to the minimum intensity in the interference pattern.

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Answer: (a)

Amplitude $\propto$ width (given), so $a_1 : a_2 = 3 : 1$ .
$\frac{I_{max}}{I_{min}} = \left(\frac{3+1}{3-1}\right)^2 = 4$
So the answer is (a) $4 : 1$ .

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