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JEE Main 2021 (26 Feb, Shift 1) · YDSE: Fringe Width & Fringe Positions

YDSE: Fringe Width & Fringe Positions question from JEE Main 2021 (26 Feb, Shift 1)

Q44JEE Main 2021 · 26 FEB · SHIFT 1Easy

YDSE: Fringe Width & Fringe Positions

In a Young's double slit experiment two slits are separated by 2 mm and the screen is placed one meter away. When a light of wavelength 500 nm is used, the fringe separation will be:

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Answer: (b)

$\beta = \frac{\lambda D}{d} = \frac{500\times10^{-9}\times 1}{2\times10^{-3}}$
$\beta = 2.5\times10^{-4}\text{ m} = 0.25$ mm, so the answer is (b).

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