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MHT CET 2019 (2 May, Shift 1) · Excess Pressure: Drops & Bubbles

Excess Pressure: Drops & Bubbles question from MHT CET 2019 (2 May, Shift 1)

Q55MHT CET 2019 · 2 MAY · SHIFT 1Difficult

Excess Pressure: Drops & Bubbles

In air, a charged soap bubble of radius ' $R$ ' breaks into 27 small soap bubbles of equal radius ' $r$ '. Then the ratio of mechanical force acting per unit area of big soap bubble to that of a small soap bubble is

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Answer: (c)

Mechanical force per unit area = excess pressure due to surface tension, $P = \frac{4T}{r} \propto \frac{1}{r}$ .
Volume conserved: $R^3 = 27r^3 \Rightarrow R = 3r$
$\frac{P_R}{P_r} = \frac{r}{R} = \frac{1}{3}$
So the answer is (c) $\frac{1}{3}$ .

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