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MHT CET 2025 (21 Apr, Shift 2) · Excess Pressure: Drops & Bubbles

Excess Pressure: Drops & Bubbles question from MHT CET 2025 (21 Apr, Shift 2)

Q23MHT CET 2025 · 21 APR · SHIFT 2Difficult

Excess Pressure: Drops & Bubbles

In air, a charged soap bubble of radius R breaks into 64 small soap bubbles of equal radius $r$ . The ratio of mechanical force per unit area of big soap bubble to that of a small bubble is

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Answer: (a)

Mechanical force per unit area = excess pressure due to surface tension, $P = \frac{4T}{r} \propto \frac{1}{r}$ .
Volume conserved: $R^3 = 64r^3 \Rightarrow R = 4r$
$\frac{P_R}{P_r} = \frac{r}{R} = \frac{1}{4}$
So the answer is (a) $1 : 4$ .

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