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MHT CET 2023 (13 May, Shift 1) · Pure R, L and C Circuits

Pure R, L and C Circuits question from MHT CET 2023 (13 May, Shift 1)

Q33MHT CET 2023 · 13 MAY · SHIFT 1Easy

Pure R, L and C Circuits

In an a.c. circuit the instantaneous current and emf are represented as I=I0sin⁡[ωt−π/6]I = I_0 \sin[\omega t - \pi/6] and E=E0sin⁡[ωt+π/3]E = E_0 \sin[\omega t + \pi/3] respectively. The voltage leads the current by

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Answer: (a)

  1. Phase of emf =ωt+π3= \omega t + \frac{\pi}{3}, phase of current =ωt−π6= \omega t - \frac{\pi}{6}.
  2. Δϕ=π3−(−π6)=π2\Delta\phi = \frac{\pi}{3} - \left(-\frac{\pi}{6}\right) = \frac{\pi}{2}
  3. So the answer is (a) π2\frac{\pi}{2}.
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