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JEE Main 2007 (AIEEE) · Power, Power Factor & Wattless Current

Power, Power Factor & Wattless Current question from JEE Main 2007 (AIEEE)

Q76JEE Main 2007 · AIEEEEasy

Power, Power Factor & Wattless Current

In an a.c.\text{a.c.} circuit the voltage applied is E=E0sin⁡ωt.E = E_0\sin\omega t. The resulting current in the circuit is I=I0sin⁡(ωt−π2).I = I_0\sin\left(\omega t - \frac{\pi}{2}\right). The power consumption in the circuit is given by

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Answer: (c)

  1. Current lags voltage by ϕ=π2\phi = \frac{\pi}{2}.
  2. P=E0I02cos⁡90∘=0P = \frac{E_0I_0}{2}\cos 90^\circ = 0
  3. So the answer is (c) P=zeroP = \text{zero}.
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