Physics Circle home Student Login

Home›Chapters›Alternating Current PYQs›Power, Power Factor & Wattless Current›Question 33

JEE Main 2024 (29 Jan, Shift 2) · Power, Power Factor & Wattless Current

Power, Power Factor & Wattless Current question from JEE Main 2024 (29 Jan, Shift 2)

Q33JEE Main 2024 · 29 JAN · SHIFT 2Easy

Power, Power Factor & Wattless Current

In an a.c. circuit, voltage and current are given by:

V=100sin⁡(100t) VV = 100\sin(100t)\text{ V} and I=100sin⁡(100t+π3) mAI = 100\sin\left(100t + \frac{\pi}{3}\right)\text{ mA} respectively.

The average power dissipated in one cycle is:

Show answer and solution

Answer: (c)

  1. P=V0I02cos⁡ϕP = \frac{V_0I_0}{2}\cos\phi with ϕ=π3\phi = \frac{\pi}{3}
  2. P=100×0.12×0.5P = \frac{100\times0.1}{2}\times0.5
  3. P=2.5 WP = 2.5\text{ W}
  4. So the answer is (c) 2.5 W.
Report a mistake

More questions on Power, Power Factor & Wattless Current