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MHT CET 2024 (11 May, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2024 (11 May, Shift 1)

Q126MHT CET 2024 · 11 MAY · SHIFT 1Medium

Thermodynamic Processes

In an adiabatic process for an ideal gas, the relation between the universal gas constant ' RR ' and specific heat at constant volume ' CvC_v ' is R=0.4CvR = 0.4C_v. The pressure ' PP ' of the gas is proportional to the temperature ' TT ', of the gas as TkT^{k}. The value of constant ' K ' is

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Answer: (a)

  1. Cp−Cv=R=0.4Cv⇒Cp=1.4CvC_p - C_v = R = 0.4C_v \Rightarrow C_p = 1.4C_v, so γ=1.4\gamma = 1.4.
  2. Adiabatic: P∝Tγ/(γ−1)P \propto T^{\gamma/(\gamma-1)}, so k=1.40.4=3.5k = \frac{1.4}{0.4} = 3.5
  3. So the answer is (a) 72\frac{7}{2}.
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