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MHT CET 2024 (10 May, Shift 2) · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from MHT CET 2024 (10 May, Shift 2)

Q41MHT CET 2024 · 10 MAY · SHIFT 2Easy

Kirchhoff's Laws & Measuring Instruments

In an ammeter, 0.25%0.25\% of main current passes through the galvanometer. If the resistance of the galvanometer is ' G ', the resistance of ammeter will be

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Answer: (b)

  1. Ig=0.25% of I=I400I_g = 0.25\% \text{ of } I = \frac{I}{400}, so S=IgGI−Ig=G399S = \frac{I_g G}{I - I_g} = \frac{G}{399}.
  2. Ammeter resistance RA=SGS+G=G/399⋅GG/399+G=G400R_A = \frac{SG}{S + G} = \frac{G/399 \cdot G}{G/399 + G} = \frac{G}{400}
  3. So the answer is (b) 1400G\frac{1}{400}G.
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