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JEE Main 2024 (1 Feb, Shift 2) · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from JEE Main 2024 (1 Feb, Shift 2)

Q46JEE Main 2024 · 1 FEB · SHIFT 2Easy

Kirchhoff's Laws & Measuring Instruments

In an ammeter, $5\%$ of the main current passes through the galvanometer. If resistance of the galvanometer is $G$ , the resistance of ammeter will be:

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Answer: (c)

$I_g = 0.05I = \frac{I}{20}$ , so $S = \frac{I_g G}{I - I_g} = \frac{G}{19}$ .
$R_A = \frac{SG}{S + G} = \frac{G/19 \cdot G}{G/19 + G} = \frac{G}{20}$
So the answer is (c) $\frac{G}{20}$ .

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