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MHT CET 2024 (15 May, Shift 2) · Electrostatic Potential Energy

Electrostatic Potential Energy question from MHT CET 2024 (15 May, Shift 2)

Q30MHT CET 2024 · 15 MAY · SHIFT 2Easy

Electrostatic Potential Energy

In an electric field due to charge QQ, a charge qq moves from point A to B as shown in the figure. The work done is ( ε0=\varepsilon_0 = permittivity of free space)

Figure

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Answer: (d)

  1. A and B both lie at distance rr from QQ (same circle), so VA=VB=kQrV_A = V_B = \dfrac{kQ}{r}.
  2. W=q(VB−VA)=0W = q(V_B - V_A) = 0
  3. So the answer is (d) zero.
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