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MHT CET 2025 (21 Apr, Shift 2) · Series LCR Circuit

Series LCR Circuit question from MHT CET 2025 (21 Apr, Shift 2)

Q21MHT CET 2025 · 21 APR · SHIFT 2Medium

Series LCR Circuit

In an electrical circuit ' RR ', ' LL ', ' CC ' and an a.c. voltage source are all connected in series. When ' L ' is removed from the circuit, the phase difference between the voltage and the current in the circuit is π3\frac{\pi}{3}. If instead ' CC ' is removed from the circuit, the phase difference is again π3\frac{\pi}{3}. The power factor of the circuit is (tan⁡π3=3)\left(\tan\frac{\pi}{3} = \sqrt{3}\right)

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Answer: (d)

  1. L removed: XC=Rtan⁡π3=3RX_C = R\tan\dfrac{\pi}{3} = \sqrt{3}R; C removed: XL=3RX_L = \sqrt{3}R.
  2. XL=XC⇒X_L = X_C \Rightarrow resonance, Z=RZ = R.
  3. Power factor =RZ=1= \dfrac{R}{Z} = 1. So the answer is (d) 1.
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