In an electrical circuit, the voltage is measured as V = (200 ± 4) volt and the current is measured as I = (20 ± 0.2) A. The value of the resistance is: (a) (10 ± 4.2) Ω (b) (10 ± 0.3) Ω (c) (10 ± 0.1) Ω (d) (10 ± 0.8) Ω

Answer: (b). R = V/I = 200/20 = 10 Ω (Δ R)/(R) = (Δ V)/(V) + (Δ I)/(I) = 4/200 + 0.2/20 = 0.02 + 0.01 = 0.03 Δ R = 0.03 × 10 = 0.3 Ω So the answer is (b) (10 ± 0.3) Ω.

In an electrical circuit, the voltage is measured as V = (200 ± 4)… | NEET 2024

Q57NEET 2024Easy

Errors in Measurement

In an electrical circuit, the voltage is measured as $V = (200 \pm 4)$ volt and the current is measured as $I = (20 \pm 0.2)$ A. The value of the resistance is:

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Answer: (b)

$R = \frac{V}{I} = \frac{200}{20} = 10\ \Omega$
$\frac{\Delta R}{R} = \frac{\Delta V}{V} + \frac{\Delta I}{I} = \frac{4}{200} + \frac{0.2}{20} = 0.02 + 0.01 = 0.03$
$\Delta R = 0.03 \times 10 = 0.3\ \Omega$
So the answer is (b) $(10 \pm 0.3)\ \Omega$ .

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