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JEE Main 2025 (4 Apr, Shift 1) · Applications of Dimensional Analysis

Applications of Dimensional Analysis question from JEE Main 2025 (4 Apr, Shift 1)

Q11JEE Main 2025 · 4 APR · SHIFT 1Easy

Applications of Dimensional Analysis

In an electromagnetic system, the quantity representing the ratio of electric flux and magnetic flux has dimension of MPLQTRASM^PL^QT^RA^S, where value of ' QQ ' and ' RR ' are

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Answer: (d)

  1. Electric flux ϕE=EA\phi_E = EA: [MLT−3A−1][L2]=[ML3T−3A−1][MLT^{-3}A^{-1}][L^2] = [ML^3T^{-3}A^{-1}].
  2. Magnetic flux ϕB=BA\phi_B = BA: [MT−2A−1][L2]=[ML2T−2A−1][MT^{-2}A^{-1}][L^2] = [ML^2T^{-2}A^{-1}].
  3. [ϕE/ϕB]=[LT−1][\phi_E/\phi_B] = [LT^{-1}] (a velocity), so Q=1Q = 1, R=−1R = -1.
  4. So the answer is (d) (1,−1)(1, -1).
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