In an electromagnetic wave in free space that root mean square value of the electric field is Erms = 6 V m ⁻¹. The peak value of the magnetic field is (a) 2.83 × 10 - 8 T (b) 0.70 × 10 - 8 T (c) 4.23 × 10 - 8 T (d) 1.41 × 10 - 8 T

Answer: (a). E₀ = √2 Erms = 6√2 = 8.49 V/m B₀ = E₀/c = 8.493×10⁸ = 2.83×10⁻⁸ T So the answer is (a) 2.83×10⁻⁸ T.

In an electromagnetic wave in free space that root mean square value… | NEET 2017

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Nature of EM Waves & Wave Equation

In an electromagnetic wave in free space that root mean square value of the electric field is Erms = 6 V m ${}^{-1}$ . The peak value of the magnetic field is

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Answer: (a)

$E_0 = \sqrt2\,E_{rms} = 6\sqrt2 = 8.49$ V/m
$B_0 = \dfrac{E_0}{c} = \dfrac{8.49}{3\times10^{8}} = 2.83\times10^{-8}$ T
So the answer is (a) $2.83\times10^{-8}$ T.

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