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MHT CET 2024 (4 May, Shift 1) · Prism, Dispersion & Scattering

Prism, Dispersion & Scattering question from MHT CET 2024 (4 May, Shift 1)

Q29MHT CET 2024 · 4 MAY · SHIFT 1Easy

Prism, Dispersion & Scattering

In an equilateral prism the ray undergoes minimum deviation when it is incident at an angle of $50^\circ$ . The angle of minimum deviation is

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Answer: (b)

At minimum deviation $i = e$ , so $\delta_m = 2i - A$ .
Equilateral prism: $A = 60^\circ$ .
$\delta_m = 2(50^\circ) - 60^\circ = 40^\circ$
So the answer is (b) $40^\circ$ .

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