In an experiment, a sphere of aluminium of mass 0.20 kg is heated… | JEE Main 2017 (8 Apr, Shift 1)

Q44JEE Main 2017 · 8 APR · SHIFT 1Medium

Calorimetry, Latent Heat & Mechanical Equivalent of Heat

In an experiment, a sphere of aluminium of mass 0.20 kg is heated upto 150oC. Immediately, it is put into water of volume 150 cc at 27oC kept in a calorimeter of water equivalent to 0.025 kg. Final temperature of the system is 40oC. The specific heat of aluminium is: (take 4.2 Joule = 1 calorie)

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Answer: (d)

Water mass $= 150\ \text{g} = 0.150\ \text{kg}$ ; add water equivalent $0.025\ \text{kg}$ .
Heat lost by Al = heat gained: $0.20\,s\,(150-40) = (0.150+0.025)(4200)(40-27)$
$22\,s = 0.175 \times 4200 \times 13 = 9555$
$s \approx 434\ \text{J/kg}^{\circ}\text{C}$
So the answer is (d) $434\ \text{J/kg}^{\circ}\text{C}$ .

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