In an experiment on photoelectric effect, a student plots stopping potential V₀ against reciprocal of the wavelength λ of the incident light for two different metals A and B. These are shown in the figure. Looking at the graphs, you can most appropriately say that: (a) Work function of metal B is greater than that of metal A (b) For light of certain wavelength falling on both metal, maximum kinetic energy of electrons emitted from A will be greater than those emitted from B. (c) Work function of metal A is greater than that of metal B (d) Students data is not correct

Answer: (d). eV₀ = (hc)/(λ) - φ, so V₀ = hc/e·(1)/(λ) - φ/e. The slope hc/e is the same for every metal, so the two lines must be parallel. The plotted lines have different slopes, which is impossible. So the answer is (d) the student's data is not correct.

In an experiment on photoelectric effect, a student plots stopping… | JEE Main 2013 (25 Apr, Shift 1)

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Photoelectric Experiment: Intensity, Stopping Potential & Graphs

In an experiment on photoelectric effect, a student plots stopping potential $V_0$ against reciprocal of the wavelength $\lambda$ of the incident light for two different metals A and B. These are shown in the figure.

Looking at the graphs, you can most appropriately say that:

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Answer: (d)

$eV_0 = \frac{hc}{\lambda} - \phi$ , so $V_0 = \frac{hc}{e}\cdot\frac{1}{\lambda} - \frac{\phi}{e}$ .
The slope $hc/e$ is the same for every metal, so the two lines must be parallel.
The plotted lines have different slopes, which is impossible.
So the answer is (d) the student's data is not correct.

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Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from JEE Main 2013 (25 Apr, Shift 1)

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