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MHT CET 2026 (19 May, Shift 1) · Photoelectric Experiment: Intensity, Stopping Potential & Graphs

Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from MHT CET 2026 (19 May, Shift 1)

Q5MHT CET 2026 · 19 MAY · SHIFT 1Easy

Photoelectric Experiment: Intensity, Stopping Potential & Graphs

In an experiment on photoelectric effect, the stopping potential $V_0$ is plotted against the frequency $\nu$ of the incident light. Considering $e$ as the electronic charge, the work function of the photoelectric surface is given by

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Answer: (c)

$V_0 = \dfrac{h}{e}\nu - \dfrac{\phi}{e}$ : a straight line with slope $h/e$ and $V_0$ -intercept $-\phi/e$ .
The intercept on the $V_0$ axis is $OB$ , so $OB = \phi/e$ (in volt), while $OA$ is the threshold frequency.
Hence $\phi = e \times OB$ in joules.
So the answer is (c).

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