Physics Circle home Student Login

Home›Chapters›Units, Dimensions and Measurement PYQs›Errors in Measurement›Question 18

JEE Main 2026 (21 Jan, Shift 1) · Errors in Measurement

Errors in Measurement question from JEE Main 2026 (21 Jan, Shift 1)

Q18JEE Main 2026 · 21 JAN · SHIFT 1Medium

Errors in Measurement

In an experiment the values of two spring constants were measured as k1=(10±0.2) N/mk_1 = (10 \pm 0.2)\text{ N/m} and k2=(20±0.3) N/mk_2 = (20 \pm 0.3)\text{ N/m}. If these springs are connected in parallel, then the percentage error in equivalent spring constant is:

Show answer and solution

Answer: (c)

  1. In parallel k=k1+k2=30 N/mk = k_1 + k_2 = 30\text{ N/m}; for a sum, absolute errors add: Δk=0.2+0.3=0.5 N/m\Delta k = 0.2 + 0.3 = 0.5\text{ N/m}
  2. Percentage error =0.530×100=1.67%= \frac{0.5}{30} \times 100 = 1.67\%
  3. So the answer is (c) 1.67%.
Report a mistake

More questions on Errors in Measurement