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MHT CET 2026 (13 Apr, Shift 2) · Potentiometer

Potentiometer question from MHT CET 2026 (13 Apr, Shift 2)

Q8MHT CET 2026 · 13 APR · SHIFT 2Easy

Potentiometer

In an experiment to find emf of a cell using potentiometer, the length of null point for a cell of emf $1.5$ V is found to be $60$ cm. If this cell is replaced by another cell of emf $E$ , the length of null point increases by $40$ cm. The value of $E$ is $x/10$ V.

The value of $x$ is

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Answer: (b)

$E \propto l$ , new length $= 60 + 40 = 100\ \text{cm}$ .
$E = 1.5 \times \frac{100}{60} = 2.5\ \text{V} = \frac{25}{10}\ \text{V}$ .
So the answer is (b) $x = 25$ .

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