In an experiment with a closed organ pipe, it is filled with water by (1/5) th of its volume. The frequency of the fundamental note will change by (a) 20% (b) 25% (c) -20% (d) -25%

Answer: (b). Closed pipe: f = v/4L, so f ∝ 1/L. Water fills 1/5 of the volume, so air column L' = 4/5L. f' = 5/4f, change = f'-f/f× 100 = +25% So the answer is (b) 25%.

In an experiment with a closed organ pipe, it is filled with water by… | JEE Main 2025 (4 Apr, Shift 1)

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Organ Pipes & Resonance Tube

In an experiment with a closed organ pipe, it is filled with water by $\left(\frac{1}{5}\right)$ th of its volume. The frequency of the fundamental note will change by

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Answer: (b)

Closed pipe: $f = \frac{v}{4L}$ , so $f \propto \frac{1}{L}$ .
Water fills $\frac{1}{5}$ of the volume, so air column $L' = \frac{4}{5}L$ .
$f' = \frac{5}{4}f$ , change $= \frac{f'-f}{f}\times 100 = +25\%$
So the answer is (b) $25\%$ .

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