In an experiment with a closed organ pipe, it is filled with water by (1/5)th of its volume. The frequency of the fundamental note will change by (a) 25% (b) 20% (c) -20% (d) -25%

Answer: (a). Closed pipe: f=v/4L. Water fills 1/5, so the air column is L'=4L/5. f'=5/4f Change =+25%, so the answer is (a).

In an experiment with a closed organ pipe, it is filled with water by… | MHT CET 2026 (15 May, Shift 2)

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Organ Pipes & Resonance Tube

In an experiment with a closed organ pipe, it is filled with water by $\left(\frac{1}{5}\right)^{th}$ of its volume. The frequency of the fundamental note will change by

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Answer: (a)

Closed pipe: $f=\frac{v}{4L}$ . Water fills $\frac{1}{5}$ , so the air column is $L'=\frac{4L}{5}$ .
$f'=\frac{5}{4}f$
Change $=+25\%$ , so the answer is (a).

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