In an experiment with sonometer when a mass of 180 g is attached to the string, it vibrates with fundamental frequency of 30 Hz. When a mass m is attached, the string vibrates with fundamental frequency of 50 Hz. The value of m is ___________ g. Numerical answer type. Work it out, then open the answer.

Answer: 500. n ∝ √(T) ∝ √(m) for the same string. m=180(50/30)²=180×25/9 m=500 g

In an experiment with sonometer when a mass of 180 g is attached to… | JEE Main 2023 (13 Apr, Shift 2)

Q70JEE Main 2023 · 13 APR · SHIFT 2Medium

Stationary Waves & Vibrating Strings

In an experiment with sonometer when a mass of $180\text{ g}$ is attached to the string, it vibrates with fundamental frequency of $30\text{ Hz}$ . When a mass $\text{m}$ is attached, the string vibrates with fundamental frequency of $50\text{ Hz}$ . The value of $\text{m}$ is ___________ g.

Numerical answer type. Work it out, then open the answer.

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Answer: 500

$n \propto \sqrt{T} \propto \sqrt{m}$ for the same string.
$m=180\left(\frac{50}{30}\right)^2=180\times\frac{25}{9}$
$m=500\text{ g}$

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