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MHT CET 2026 (17 Apr, Shift 1) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2026 (17 Apr, Shift 1)

Q23MHT CET 2026 · 17 APR · SHIFT 1Medium

Thermal Radiation: Black Body, Stefan & Wien

In an external environment of temperature (TT) kelvin, a sphere at temperature (3T3T) kelvin has cooling rate R1R_1. When the temperature of that sphere falls to (2T2T) kelvin, the cooling rate R2R_2 of the sphere will become

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Answer: (d)

  1. Net rate of cooling ∝Ts4−T4\propto T_s^4 - T^4.
  2. At 3T3T: (81−1)T4=80T4(81 - 1)T^4 = 80T^4; at 2T2T: (16−1)T4=15T4(16 - 1)T^4 = 15T^4
  3. R2=1580R1=316R1R_2 = \dfrac{15}{80}R_1 = \dfrac{3}{16}R_1
  4. So the answer is (d).
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