In an ideal junction diode, the current flowing through PQ is (a) 2 × 10 ⁻³ A (b) 2 × 10 ⁻² A (c) 4 × 10 ⁻³ A (d) 10 ⁻³ A

Answer: (c). The anode is at P ( +3 V) and the circuit ends at Q ( -5 V), so the diode is forward biased. I = (VP - VQ)/(R) = 3 - (-5)2× 10³ I = 8/2000 = 4× 10⁻³ A So the answer is (c) 4× 10⁻³ A.

In an ideal junction diode, the current flowing through PQ is | MHT CET 2021 (21 Sep, Shift 2)

Q73MHT CET 2021 · 21 SEP · SHIFT 2Medium

P-N Junction Diode

In an ideal junction diode, the current flowing through PQ is

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Answer: (c)

The anode is at P ( $+3$ V) and the circuit ends at Q ( $-5$ V), so the diode is forward biased.
$I = \dfrac{V_P - V_Q}{R} = \dfrac{3 - (-5)}{2\times 10^{3}}$
$I = \dfrac{8}{2000} = 4\times 10^{-3}$ A
So the answer is (c) $4\times 10^{-3}$ A.

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