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MHT CET 2024 (4 May, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2024 (4 May, Shift 1)

Q109MHT CET 2024 · 4 MAY · SHIFT 1Medium

Thermodynamic Processes

In an isobaric process of an ideal gas, the ratio of work done by the system to the heat supplied (WQ)\left(\frac{W}{Q}\right) is

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Answer: (d)

  1. Isobaric: W=nRΔTW = nR\Delta T, Q=nCpΔTQ = nC_p\Delta T.
  2. WQ=RCp=1−CvCp=γ−1γ\frac{W}{Q} = \frac{R}{C_p} = 1 - \frac{C_v}{C_p} = \frac{\gamma - 1}{\gamma}
  3. So the answer is (d) γ−1γ\frac{\gamma - 1}{\gamma}.
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