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MHT CET 2024 (9 May, Shift 2) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2024 (9 May, Shift 2)

Q106MHT CET 2024 · 9 MAY · SHIFT 2Medium

Thermodynamic Processes

In an isobaric process of an ideal gas, the ratio of work done by the system (W) during the expansion and the heat exchanged (Q)(Q) is (γ=CpCv)\left(\gamma = \frac{C_p}{C_v}\right)

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Answer: (d)

  1. Isobaric: W=nRΔTW = nR\Delta T, Q=nCpΔTQ = nC_p\Delta T.
  2. WQ=RCp=Cp−CvCp=1−1γ=γ−1γ\frac{W}{Q} = \frac{R}{C_p} = \frac{C_p - C_v}{C_p} = 1 - \frac{1}{\gamma} = \frac{\gamma - 1}{\gamma}
  3. So the answer is (d) γ−1γ\frac{\gamma - 1}{\gamma}.
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