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JEE Main 2013 · Inductors & DC Transients (Mixed)

Inductors & DC Transients (Mixed) question from JEE Main 2013

Q27JEE Main 2013Difficult

Inductors & DC Transients (Mixed)

In an LCRLCR circuit as shown below both switches are open initially. Now switch S1S_1 is closed, S2S_2 kept open. (qq is charge on the capacitor and τ=RC\tau = RC is Capacitance time constant). Which of the following statements is correct?

Figure

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Answer: (c)

  1. With S1 closed and S2 open, C charges through R: q=CV(1−e−t/τ)q = CV(1 - e^{-t/\tau}).
  2. (a) is wrong: battery work =CV2= CV^2, heat in R =12CV2= \frac{1}{2}CV^2, so work is twice the heat.
  3. (b) is wrong: at t=τt = \tau, q=CV(1−e−1)≈0.63 CVq = CV(1 - e^{-1}) \approx 0.63\,CV.
  4. (c) is right and (d) is wrong: at t=2τt = 2\tau, q=CV(1−e−2)q = CV(1 - e^{-2}).
  5. So the answer is (c).
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