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MHT CET 2024 (16 May, Shift 2) · Series LCR Circuit

Series LCR Circuit question from MHT CET 2024 (16 May, Shift 2)

Q22MHT CET 2024 · 16 MAY · SHIFT 2Easy

Series LCR Circuit

In an $LCR$ circuit, if ' $V$ ' is the effective value of the applied voltage, $V_R$ is the voltage across ' $R$ ', ' $V_L$ ' and ' $V_C$ ' is the effective voltage across ' L ' and ' $C$ ' respectively then

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Answer: (c)

$V_R$ is in phase with current; $V_L$ leads by $90^\circ$ and $V_C$ lags by $90^\circ$ , so they subtract.
Phasor sum: $V^2 = V_R^2 + (V_L - V_C)^2$
So the answer is (c).

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