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MHT CET 2025 (25 Apr, Shift 2) · RL and RC Series Circuits

RL and RC Series Circuits question from MHT CET 2025 (25 Apr, Shift 2)

Q11MHT CET 2025 · 25 APR · SHIFT 2Easy

RL and RC Series Circuits

In an $LR$ circuit, the value of $L$ is $\left(\frac{0.3}{\pi}\right)$ henry and the value of R is $40\ \Omega$ , If in the circuit, an alternating e.m.f of 230 V at 50 cycles per second is connected, the impedance of the circuit and current will be respectively

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Answer: (d)

$X_L = 2\pi f L = 2\pi \times 50 \times \frac{0.3}{\pi} = 30\ \Omega$
$Z = \sqrt{40^2 + 30^2} = 50\ \Omega$
$I = \frac{230}{50} = 4.6$ A
So the answer is (d) $50\ \Omega,\ 4.6$ A.

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