In an n-p-n common emitter (CE) transistor the collector current changes from 5 mA to 16 mA for the change in base current from 100 and 200, respectively. The current gain of transistor is __________. (a) 210 (b) 0.9 (c) 9 (d) 110

Answer: (d). β = (Δ IC)/(Δ IB) Δ IC = 16 - 5 = 11 mA, Δ IB = 100 μ A = 0.1 mA β = 11/0.1 = 110 So the answer is (d) 110.

In an n-p-n common emitter (CE) transistor the collector current… | JEE Main 2023 (12 Apr, Shift 1)

Q44JEE Main 2023 · 12 APR · SHIFT 1Easy

Junction Transistor

In an n-p-n common emitter (CE) transistor the collector current changes from 5 $\text{mA}$ to $16\text{ mA}$ for the change in base current from $100\,\mu\text{A}$ and $200\,\mu\text{A}$ , respectively. The current gain of transistor is __________.

Show answer and solution

Answer: (d)

$\beta = \frac{\Delta I_C}{\Delta I_B}$
$\Delta I_C = 16 - 5 = 11$ mA, $\Delta I_B = 100\,\mu$ A $= 0.1$ mA
$\beta = 11/0.1 = 110$
So the answer is (d) 110.

Report a mistake

Junction Transistor question from JEE Main 2023 (12 Apr, Shift 1)

More questions on Junction Transistor