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MHT CET 2025 (20 Apr, Shift 2) · Junction Transistor

Junction Transistor question from MHT CET 2025 (20 Apr, Shift 2)

Q29MHT CET 2025 · 20 APR · SHIFT 2Medium

Junction Transistor

In an n-p-n transistor amplifier, the collector current is 9 mA. If 90%90\% of the electrons emitted reach the collector, then

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Answer: (c)

  1. α=0.9⇒IE=90.9=10\alpha = 0.9 \Rightarrow I_E = \dfrac{9}{0.9} = 10 mA, IB=10−9=1I_B = 10 - 9 = 1 mA.
  2. β=91=9\beta = \dfrac{9}{1} = 9 (check: β=α1−α=0.90.1=9\beta = \dfrac{\alpha}{1-\alpha} = \dfrac{0.9}{0.1} = 9).
  3. So the answer is (c) α=0.9,β=9\alpha = 0.9, \beta = 9.
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