In an n-p-n transistor amplifier, the collector current is 8 mA. If 80% of the electrons from the emitter reach the collector, then ( α and β are current ratios) (a) the base current is 20 mA. (b) the emitter current is 2 mA. (c) α = 0.8, β = 4.0 (d) α = 4.0, β = 0.8

Answer: (c). α = (IC)/(IE) = 0.8 ⇒ IE = 8/0.8 = 10 mA. IB = 10 - 8 = 2 mA. β = (IC)/(IB) = 8/2 = 4 So the answer is (c) α = 0.8, β = 4.0.

In an n-p-n transistor amplifier, the collector current is 8 mA. If… | MHT CET 2025 (21 Apr, Shift 1)

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Junction Transistor

In an n-p-n transistor amplifier, the collector current is 8 mA. If $80\%$ of the electrons from the emitter reach the collector, then ( $\alpha$ and $\beta$ are current ratios)

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Answer: (c)

$\alpha = \dfrac{I_C}{I_E} = 0.8 \Rightarrow I_E = \dfrac{8}{0.8} = 10$ mA.
$I_B = 10 - 8 = 2$ mA.
$\beta = \dfrac{I_C}{I_B} = \dfrac{8}{2} = 4$
So the answer is (c) $\alpha = 0.8, \beta = 4.0$ .

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