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MHT CET 2026 (13 May, Shift 2) · Junction Transistor

Junction Transistor question from MHT CET 2026 (13 May, Shift 2)

Q11MHT CET 2026 · 13 MAY · SHIFT 2Medium

Junction Transistor

In an n-p-n transistor the collector current is $9$ mA. If $90\%$ of the electrons from the emitter reach the collector then

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Answer: (a)

$\alpha = 0.9$ , so $I_E = \dfrac{I_C}{\alpha} = \dfrac{9}{0.9} = 10$ mA.
$I_B = I_E - I_C = 10 - 9 = 1$ mA.
$\beta = \dfrac{I_C}{I_B} = \dfrac{9}{1} = 9$
So the answer is (a) $\beta = 9.0$ .

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